0.3y^2-50.7=0

Solution for 0.3y^2-50.7=0 equation:

0.3y^2-50.7=0

a = 0.3; b = 0; c = -50.7;
Δ = b2-4ac
Δ = 02-4·0.3·(-50.7)
Δ = 60.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{60.84}}{2*0.3}=\frac{0-\sqrt{60.84}}{0.6}
=-\frac{\sqrt{}}{0.6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{60.84}}{2*0.3}=\frac{0+\sqrt{60.84}}{0.6}
=\frac{\sqrt{}}{0.6}
$